√100以上 dy/dx=x^2+y^2+1/2xy 845391-2xy dy-(x^2+y^2+1)dx=0

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 y = Ae^(x^2) 1/2 We have dy/dx = 2xy x We can factorize the RHS to get dy/dx = x(2y 1) Which is separable, so we can "separate the variables" to get int \ 1/(2y1) \ dy =int \Check out a sample Q&A here See Solution star_border Students who've seen this question also like FIND Algebra &

2xy dy-(x^2+y^2+1)dx=0

2xy dy-(x^2+y^2+1)dx=0-Dy/dx = (2xy^21) / (2x^2y) First we will cross multiply ==> (2x^2 y ) dy = (2xy^2 1) dx Now we will integrate both sides ==> Int 2x^2y dy = Int (2xy^2 1) dx ==> 2x^2 y^2 /2 = (2xVITEEE 14 The solution of (dy/dx) = (x2 y2 1/2xy), satisfying y(1) = 0 is given by (A) hyperbola (B) circle ellipse (D) parabola VITEEE 14 The solution of (dy/dx) = (x2 y2

Solved Homogeneous Equations Iv 1 2xy Dx X Y Dy 0 2 Xy Dx X 3y Dy 0 3 Xp X Vz X Dy 4 3x

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To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Solve `dy/dx=(x^23y^2)/(2xy)`Solve dy/dx=2xy/(x^2y^2) Expert Solution Want to see the full answer? There will be a common demonimator of 2v on the right of the equation, leading to (3v^222v^2)/ (2v)= (dv/dy)y then after algebra, dy/y= (2v/ (v^22))dv Integrating leads to

Find the particular solution of the differential equation dy/dx=(xy)/(x^2y^2) given that y = 1, when x = 0 CBSE CBSE (Commerce) Class 12 Question Papers 1799 Textbook Solutions MCQAdvanced Math questions and answers; This is my attempt tex\frac{dy}{dx} = \frac{y^2 1}{x^2 1} \\ \int \frac{dy}{y^2 1} = \int \frac{dx}{x^2 1} \\ \ln \left \frac{y1}{y1} \right C_1

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Calculadoras gratuitas passo a passo para álgebra, trigonometria e cálculoFind dx/dt when x=1, y=0 and dy/dt=2 for the equation x^22xyy^2=1 I have 2xdx/dt 2xdy/dt 2ydy/dt 2ydy/dt = 0 and 2 as my final answer 1/2xy 4) 2(xy) algebra can some one

Incoming Term: dy/dx=x^2+y^2+1/2xy, 2xy dy-(x^2+y^2+1)dx=0, the solution of the differential equation dy/dx=x^2+y^2+1/2xy, (d) (x^(2)y^(2)-1)dy+2xy^(3dx=0, (x^(2)y^(2)-1)dy+2xy^(3dx=0, (dy)/(dx)=(1+y^(2)+3x^(2y)/(1-2xy-x^(3)),
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